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2x^2+60x-21600=0
a = 2; b = 60; c = -21600;
Δ = b2-4ac
Δ = 602-4·2·(-21600)
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{176400}=420$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-420}{2*2}=\frac{-480}{4} =-120 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+420}{2*2}=\frac{360}{4} =90 $
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